Solving The Leap Year Problem 

Step-by-Step Solution

Step 1: Accepting User Input 

The code begins by importing the Scanner class from java.util package, which is used for taking input from the user.

The LeapYear class contains a main method, which is the entry point of the program. Inside the main method:

1. • It creates a new Scanner object named scanner to read input from the console.

   • Asks the user to enter a year by displaying the message "Enter a year: ".

   • Reads the integer input provided by the user and stores it in the variable year.

Step 2: Determine if the input year is leap year or not

main method calls the isLeapYear method with the input year as an argument to check if it's a leap year or not.

The isLeapYear method takes an integer year as input and returns a boolean value (true if the year is a leap year, false otherwise).

1. • It checks if the input year is divisible by 4 using the condition year % 4 == 0. If true, it proceeds to the next step.

   • If the year is divisible by 4, it checks if it's also divisible by 100 using the condition year % 100 == 0.

     • If true, it further checks if the year is divisible by 400 using the condition year % 400 == 0.

       • If all conditions (year % 4 == 0, year % 100 == 0, year % 400 == 0) are true, it returns true, indicating that the year is a leap year.

     • If the year is not divisible by 400, it returns false, indicating that the year is not a leap year.

   • If the year is not divisible by 4, the method directly returns false, indicating that the year is not a leap year.

Step 3: Prints the result 

print the result based on the return value of isLeapYear.

Conclusion

In this article, we discussed the leap year problem, its conditions, and provided a step-by-step solution and code to determine whether a given year is a leap year or not. This problem is a good example of using conditional statements to solve a real-world problem.